a solid is in the form of a right circular cylinder with hemisphere at one end and a cone at the other end. the radius of the commom base is 8cm and the heights of the cylindrical and conical portion are 10cm and 6cm respectively. Find the total surface area of the solid use pi=3. 14
Answers
Step-by-step explanation:
A solid is in the form of a right circular cylinder, with a hemisphere at one end and a cone at the other end. The radius of the common base is 8 cm and the heights of the cylindrical and conical portions are 10cm and 6cm respectively. Find the total surface area of the solid. (Use π=22/7)
Answer:
2662.72 cm^2
Step-by-step explanation:
height of cylinder (H) = 10 cm
height of the cone (h) = 6 cm
Radius of cylinder = radius of cone = radius of hemisphere = 8 cm
Slant height of cone (l) = √h^2 + r^2
= √ 6^2 + 8^2 = √ 36 + 64 = √ 100 = 10cm
Total surface area of the solid =
Curved surface area of cylinder + C.S.A of cone + C.S.A of hemisphere
= πr^2h + πrl + 2πr^2
= 3.14 × 8^2 × 10 + 3.14 × 8 × 10 + 2 × 3.14 × 8^2
= 3.14 × 8 × 2 ( 4 × 10 + 5 + 8 )
= 50.24 ( 40 + 13 )
= 50.24 × 53
= 2662.72 cm ^2