Question

a solid is in the form of a right circular cylinder with a hemisphere at one end and a cone on the other. the height and radius of the cylindrical part are 13 and 5 cm. calculate the surface area of the day if the height of the conical part is 12 cm



give me the correct answer !!!plss​

Answer 1

Answer:

Surface area of the figure = 770cm²

Step-by-step explanation:

Surface area of the figure

Surface area of the figure= 2πrh+2πr²+πrl

Surface area of the figure= 2πrh+2πr²+πrll=√(r²+H²)=√(5²+12²)=13cm

Surface area of the figure= 2πrh+2πr²+πrll=√(r²+H²)=√(5²+12²)=13cmSurface area of the figure

Surface area of the figure= 2πrh+2πr²+πrll=√(r²+H²)=√(5²+12²)=13cmSurface area of the figure= πr(2h+2r+l) = (22/7)×5(26+10+13)

Surface area of the figure= 2πrh+2πr²+πrll=√(r²+H²)=√(5²+12²)=13cmSurface area of the figure= πr(2h+2r+l) = (22/7)×5(26+10+13)= (22/7)×5×49 = 770cm²