Question

A solid is in the form of a right circular cylinder with a hemisphere one end and a cone at the other end. The radius of the common base is 8 cm. and the heights of the cylindrical and conical portion are 10 cm and 6 cm respectively. Find the total surface area of the solid.
(use π = 3.14)

Answer 1

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$<b><u>$Given that, radius(r) is 8 cm, height of cylinder(H) is 10 cm and height of cone(h) is 6cm.
Also, l = √ r2 + h2
⇒ l = √ 82 + 62
⇒ l = √ 64 + 36
⇒ l = √ 100
⇒ l = 10
Now, total surface area of solid = surface area of cone + surface area of cylinder + surface area of sphere
⇒ total surface area of solid = πrl + 2πrH + 2πr2 = πr(l + 2H + 2r)
= 3.14 × 8(10 + 2 × 10 + 2 × 8)
= 3.14 × 8 × 46
= 1155.55 cm2