Question

a solid is in the form of cone mounted on a hemisphere in such a way that the centre of the base of the cone just coincide with the centre of the base of the hemisphere. Slant height of the cone is l and radius of the base of the cone is r/2, where r is the radius of the hemisphere. Prove that the total surface area of the solid is π/4(11r+2l)r sq unit.​

Answer 1

Answer:

A solid is in the form of cone mounted on a hemisphere in such a way that the centre of the base of the cone just coincide with the centre of the base of the hemisphere. Slant height of the cone is L and radius of the base of the cone is 1/2r where through r is the radius of the hemisphere. Prove that the surface area of the solid is pie/4 (11r+ 2L) r sq. units.

Step-by-step explanation:

a solid is in the form of cone mounted on a hemisphere in such a way that the centre of the base of the cone just coincide with the centre of the base of the hemisphere. Slant height of the cone is l and radius of the base of the cone is r/2, where r is the radius of the hemisphere. Prove that the total surface area of the solid is π/4(11r+2l)r sq unit.