Question

a solid is in the form of frustum of cone the diameter of 8 cm and 10 cm and its slant height is 8 cm find C S A of a solid (use- 3.14)​

Answer 1

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▪︎ Diameter of small end = 8cm

=》 Radius (r) = 8cm/2 = 4cm.

▪︎ Diameter of large end = 10cm.

=》 Radius (R) = 10cm/2 = 5cm.

▪︎ Slant height (l) = 8cm

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▪︎ C.S.A of the frustum.

${\large{\blue{\bold{\underline{Formula\:Used:-}}}}}$

▪︎ pie×l (R+r).

${\large{\blue{\bold{\underline{Now,}}}}}$

▪︎ C.S.A = pie×l(R+r).

= 3.14 × 8cm (5cm+4cm).

= 25.12cm (9cm).

${\small{\red{\boxed{\bold{=\:226.08\:Cm\:Square.}}}}}$

☆ Therefore the required C.S.A is 226.08 cm².

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