Question

A solid metal cube of edge length 4 cm is moving in a positive Y-direction at a constant speed of 12m/s.
There is a uniform magnetic field of 0.2T in the positive Z-direction. The potential difference between the
two faces of the cube perpendicular to the X-axis is
o 24 mV
o 36 mV
96 mV
48 mv​

Answer 1

Answer:96Mv

Explanation:

as we know P.D is bvl

b=0.2t

v=12m/s

a=4cm

BVL=0.2*12*4

96*10^-3

96 mV

THIS IS P CHOWDARY

Answer 2

Concept:

The potential difference between the two faces of cube perpendicular to x-axis is given by $E=Bvl$ where,

$B$ is the magnetic field

$v$ is the speed

$l$ is the edge length

Given:

Edge length of metal cube is 4cm moving with 12m/s speed in a uniform magnetic field of 0.2T.

To Find:

We have to find the potential difference between the two faces of the cube perpendicular to x-axis.

Solution:

By considering the given data,

$E=Bvl=0.2*12*4*10^{-2}$

$E=96 mV$

Hence the potential difference between the two faces of cube perpendicular to x-axis is $96 mV$

#SPJ2