a solid metal sphere is recast into many smaller sphere calculate the number of sphere if the initial raddi is 10cm and final radius is 2cm
Answers
Answer:
no.of spheres= volume of big sphere÷volumeof smaller spher
(4/3×22/7×10×10×10)÷(4/3×22/7×2×2×2)
=10×10×10/2×2×2
=125
The number of small spheres = 125
Given:
A solid metal sphere is recast into many smaller spheres
Initial radius = 10 cm
And final radius = 2 cm
To find:
The number of small spheres
Solution:
Given initial radius of sphere = 10 cm
Volume of the sphere = 4/3 π r³
= (4/3)(22/7)(10)³ cm³
The sphere is melted and recast into many smaller spheres
Radius of each small sphere = 2 cm
Volume of each small ball = (4/3)(22/7)(2³) cm³
Let n be the number small spheres
Sum of volume of all small spheres = n [(4/3)(22/7)(2³) ]
As we know
The volume of initial sphere = Sum of volume of all small spheres
⇒ (4/3)(22/7)(10)³ = n [(4/3)(22/7)(2³) ]
⇒ 10³ = n (2³)
⇒ n = 1000/8
⇒ n = 125
Therefore,
The number of small spheres = 125
#SPJ2
The number of small spheres = 125
Given:
A solid metal sphere is recast into many smaller spheres
Initial radius = 10 cm
And final radius = 2 cm
To find:
The number of small spheres
Solution:
Given initial radius of sphere = 10 cm
Volume of the sphere = 4/3 π r³
= (4/3)(22/7)(10)³ cm³
The sphere is melted and recast into many smaller spheres
Radius of each small sphere = 2 cm
Volume of each small ball = (4/3)(22/7)(2³) cm³
Let n be the number small spheres
Sum of volume of all small spheres = n [(4/3)(22/7)(2³) ]
As we know
The volume of initial sphere = Sum of volume of all small spheres
⇒ (4/3)(22/7)(10)³ = n [(4/3)(22/7)(2³) ]
⇒ 10³ = n (2³)
⇒ n = 1000/8
⇒ n = 125
Therefore,
The number of small spheres = 125
#SPJ2