A solid metal sphere of 6 cm diameter is melted and a cylinder of thickness 2 cm is prepared.Find the diameter of the cylinder.
Answers
Answer:
The diameter of the cylinder prepared by melting of the sphere is 6√2cm
Step-by-step explanation:
Given ,
• the diameter of a solid metal sphere, d = 6cm
so the radius of the sphere , r = 3cm
Now the volume of the solid sphere is
Again , in the question we are given that
The solid sphere is melted to form a cylinder of thickness 2cm ,
Therefore ,
Volume of solid sphere = Volume of cylinder
Thus the radius of the prepared cylinder is 3√2cm
So , the diameter of the cylinder is 2×radius = 6√2cm
✬ Diameter = 6√2 cm ✬
Step-by-step explanation:
Given:
- Diameter of solid metal sphere is 6 cm.
- Height or thickness of Cylinder is 2 cm.
To Find:
- What is the diameter of the cylinder?
Solution: We know that Radius = Diameter/2
∴ Radius of sphere = 6/2 = 3 cm.
★ Volume of Sphere =
4/3π(3)³
4/3π27cm³
36π cm³
Since, The sphere is melted to form a cylinder therefore, Volume of Sphere = Volume of Cylinder.
★ Volume of Cylinder = πr²h ★
πr²2
2πr²
A/q
36π cm³ = 2πr cm²
36π cm³/2πr cm² = 0
18π cm
3√2 cm
Hence, The radius of Cylinder is 3√2 cm therefore its diameter will be 2 x 3√2 = 6√2 cm