A solid metallic cuboid of dimensions 10 cm × 5 cm × 3 cm is melted and cast into a box of thickness .5 cm without lid. If the outer measurements of base of box are 12 cm and 5 cm.find the height of the box
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volume of cuboid = length * breadth * height
= 10*5*3
= 150 cm cube
volume of cuboid = volume of box
dimensions of box= l= 12 and 11.5cm
= b = 5 and 4.5cm
= h = H and H-0.5 cm *
volume of box = 12*5*H - 11.5*4.5*H-0.5
= 60H - (11.5 * 4.5 * H-0.5)
according to question= 150=60H - (51.75H - 25.875)
150 = 60H - 51.75H + 25.875
150- 25.875 = 8.25H
124.125 = 8.25H
H = 12412.5/ 825
H = 15.04cm
so height of the box is 15.04 cm.
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= 10*5*3
= 150 cm cube
volume of cuboid = volume of box
dimensions of box= l= 12 and 11.5cm
= b = 5 and 4.5cm
= h = H and H-0.5 cm *
volume of box = 12*5*H - 11.5*4.5*H-0.5
= 60H - (11.5 * 4.5 * H-0.5)
according to question= 150=60H - (51.75H - 25.875)
150 = 60H - 51.75H + 25.875
150- 25.875 = 8.25H
124.125 = 8.25H
H = 12412.5/ 825
H = 15.04cm
so height of the box is 15.04 cm.
plzzzzz Mark this question as branliest question
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