A solid metallic cylinder rod of diameter 1cm and length 8cm is drawn into a cylindrical wire of length 18m of uniform thivkness. find the thivkness of wire
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herevolume of cylinder rod = volume of wire
volume of rod=pir^2h
=pi1/4.8
=2pi
volume of wire =pir^2h
=pir^2.18
since both volumes are equal r^2=2/18
=1/9 so r=1/3
since thinkness of wire= diameter =2/3mm=0.67mm
volume of rod=pir^2h
=pi1/4.8
=2pi
volume of wire =pir^2h
=pir^2.18
since both volumes are equal r^2=2/18
=1/9 so r=1/3
since thinkness of wire= diameter =2/3mm=0.67mm
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