a solid metallic cylindrical rod of diameter 1 cm and lenght 8 cm is drawn into a cylindrical wire of lenght 18 m of uniform thickness find the thickness of the wire
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Cylindrical rod:
Diameter (D) = 1 cm
⇒ Radius (R) =
Height of rod (H) = length of rod = 8 cm
∴ Volume of rod = πR2H
Cylindrical rod is drawn into a cylindrical wire of length (h) 18 m (= 1800 cm)
∴ Volume of cylindrical rod = volume of cylindrical wire
Let r be the radius of cross-section of the wire.
So, the diameter of the cross-section (approx)
Hence, thickness of the wire = 0.67 mm
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sumanguptaaryan:
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