Question

A solid metallic hemisphere of diameter 8 cm is melted and recasted into a right circular cone. waht is the height of cone ?

Answer 1

height is 16cm my friend if any questions ask me

Answer 2

Let h cm be the height of the cone. Then, .Volume of the area = Volume of the hemisphere

= $\sf{ \frac{1}{3} \pi {(6)}^{2} h = \frac{2}{3} \pi {(8)}^{3} }$

$\therefore$ $\sf{h = \frac{2 \times 8 \times 8\times 8}{6 \times 6} = 28.44cm}$