A solid metallic right circuler cone 20cm high and whose vertical angle is60degree;is cut into two parts at the middle of its height by a plane parellel to its base.if the frustum so obtained be drawn into a wire of diameter1/12cm;find the length of the wire
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volume of frustum = big cone -small cone
Vcone = 1/3 × pi × r2 × h
Vs = 1/3 × pi × r2 × h where r=10√3, h=10
Vb = 1/3 × pi × r2 × h where r=20√3, h=20
note Vb= 8*Vs
Vcone = Vwire = pi (1/24)^2*length
length = 24^2*7/3*100*3*10
=40.32km
Vcone = 1/3 × pi × r2 × h
Vs = 1/3 × pi × r2 × h where r=10√3, h=10
Vb = 1/3 × pi × r2 × h where r=20√3, h=20
note Vb= 8*Vs
Vcone = Vwire = pi (1/24)^2*length
length = 24^2*7/3*100*3*10
=40.32km
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