A solid metallic rod 15 cm long with diameter equal to 3.5 cm is melted and made in to another rod of radius 3.5 cm what will be the length of the new rod
rahulroy1:
fast sovle
Answers
Answered by
44
15 x 3.5/2 x 3.5/2 x 3.14 = l x 3.5 x 3.5 x 3.14
15 x 3.5/2 x 3.5/2 x 3.14/3.14 = l x 12.25
15 x 12.25/4x12.25 = l
15 x 1/4 = l
15/4 = l
3.75 = l
15 x 3.5/2 x 3.5/2 x 3.14/3.14 = l x 12.25
15 x 12.25/4x12.25 = l
15 x 1/4 = l
15/4 = l
3.75 = l
Answered by
30
here is the solution
Attachments:
Similar questions