A solid metallic rod 15cm long with diameter equal to 3.5 cm is melted and made in to another rod of radius 3.5 cm. what will be the length of the new rod?
Answers
Answered by
4
Answer:
Length of second rod = 15/4
= 3.75 cm
Step-by-step explanation:
Length of first rod = 15 cm
Radius of first rod = 3.5/2 cm
Volume of first rod = pi *r*r*h
= pi * 3.5 * 3.5 * 15 / 4 cm^3 --------
Radius of second rod = 3.5 cm
Volume of second rod = Volume of first rod
=> pi * 3.5 * 3.5* h = pi *3.5*3.5*15 / 4
=> h = 15/4
Length of second rod = 15/4
= 3.75 cm
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Answered by
4
Answer:
Length of first rod = 15 cm
Radius of first rod = 3.5/2 cm
Volume of first rod = pi *r*r*h
= pi * 3.5 * 3.5 * 15 / 4 cm^3 --------
Radius of second rod = 3.5 cm
Volume of second rod = Volume of first rod
=> pi * 3.5 * 3.5* h = pi *3.5*3.5*15 / 4
=> h = 15/4
Length of second rod = 15/4
= 3.75 cm
Step-by-step explanation:
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