Physics, asked by aradhya6804, 10 months ago

A solid metallic sphere is rotating about its diameter with constant angular speed omega if it's summer

Answers

Answered by Anonymous
186

Answer:

Given that a solid metal sphere is rotating about its diameter with a constant angular speed. It is heated and its temperature increases appreciably. We assume that all heat energy has been used for expansion of the sphere.

Due to coefficient of volume expansion of the metal of the sphere, there is increase in the volume of the sphere. It is same as saying that radius of the sphere increases.

Now rotational kinetic energy of sphere is given as

KE_{rot}=\frac{1}{2}I\omega^2 ........(1)

Also, moment of inertia is given as

I = \frac {2}{5}MR^2 .........(2)

In the absence of any external turning moment/torque, rotational kinetic energy must be conserved.

From equation (2) we see that with the increase of radius, moment of inertia of the sphere increases. From (1) we infer that in order to conserve rotational kinetic energy, \omega must decrease.

.-.-.-

Alternatively, angular momentum of rotating sphere

I = I \omega......(3)

Since there is no external torque, angular momentum needs to be conserved. With the help of (2) and (3) we arrive at the same result.

Answered by DeviIQueen
3

Answer:

Given that a solid metal sphere is rotating about its diameter with a constant angular speed. It is heated and its temperature increases appreciably. We assume that all heat energy has been used for expansion of the sphere.

Due to coefficient of volume expansion of the metal of the sphere, there is increase in the volume of the sphere. It is same as saying that radius of the sphere increases.

Now rotational kinetic energy of sphere is given as

KE_{rot}=\frac{1}{2}I\omega^2 ........(1)KE

rot

=

2

1

2

........(1)

Also, moment of inertia is given as

I = \frac {2}{5}MR^2 .........(2)I=

5

2

MR

2

.........(2)

In the absence of any external turning moment/torque, rotational kinetic energy must be conserved.

From equation (2) we see that with the increase of radius, moment of inertia of the sphere increases. From (1) we infer that in order to conserve rotational kinetic energy, \omegaω must decrease.

.-.-.-

Alternatively, angular momentum of rotating sphere

I = I \omega......(3)I=Iω......(3)

Since there is no external torque, angular momentum needs to be conserved. With the help of (2) and (3) we arrive at the same result.

Similar questions