Math, asked by Rajuchakma9732, 11 months ago

A solid metallic sphere of diameter 28 cm is melted and recast into a number of smaller cones, each of diameter 4 2/3 cm and height 3cm. Find the number of cones so formed.

Answers

Answered by Anonymous
14

Answer:

672

Step-by-step explanation:

Diameter of the sphere = 28 cm

Thus, radius of the sphere = 28/2 = 14 cm

Diameter of cone = 14/3 cm  

Thus, radius of the cone = 14/3 / 2

radius of cone = 7/3

Volume of the sphere = 4/3πr³

Volume of cone =  1/3πr²h

Number of cones = Volume of sphere/Volume of cone

= (4/3 × 14 × 14 × 14)/(1/3 × 7/3 × 7/3 × 3)

= 10976 × 9/147

= 672

Therefore, the number of cones so formed is 672.

Answered by Anonymous
8

Answer:

Step-by-step explanation:

Diameter of the sphere = 28 cm

Thus, radius of the sphere = 28/2 = 14 cm

Diameter of cone = 14/3 cm

Thus, radius of the cone = 14/3 / 2

radius of cone = 7/3

Volume of the sphere = 4/3πr³

Volume of cone = 1/3πr²h

Number of cones = Volume of sphere/Volume of cone

= (4/3 × 14 × 14 × 14)/(1/3 × 7/3 × 7/3 × 3)

= 10976 × 9/147

= 672

Therefore, the number of cones so formed is 672.

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