Question

A solid metallic sphere of radius 14 cm is cut into 2 halves . Find the total surface area of 2 hemisphere so formed

Answer 1

Answer:

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Answer 2

$\large\bf\underline {To \: find:-}$

• Total surface area of 2 hemisphere.

$\large\bf\underline{Given:-}$

• Radius of sphere = 14cm

$\huge\bf\underline{Solution:-}$

Radius of sphere = Radius of Hemisphere = 14cm

✥Total surface area of Hemisphere = 3πr²

$\: \: \: \: \: \tt \dashrightarrow \: 3 \times \frac{22}{7} \times {14}^{2} \\ \\ \: \: \: \: \: \tt \dashrightarrow \: 3\times \frac{22}{ \cancel7} \times \cancel{196} \\ \\ \: \: \: \: \: \tt \dashrightarrow \: 3 \times 22 \times 28 \\ \\ \: \: \: \: \: \tt \dashrightarrow \: 1848 {cm}^{2}$

Hence,

Total surface area of each hemisphere is 1848cm²

$\rule{200}3$

✍Formula's related to hemisphere:-

»★CSA of hemisphere = 2πr²

»★TSA of hemisphere = 3πr²

»★Volume of hemisphere = ⅔πr²

where,

• ≫TSA = Total Surface Area
• ≫CSA = Curved Surface Area

$\rule{200}3$