A solid metallic spherical ball of radius 4 cm recast into three solid metallic spherical balls
whose radil are 2 cm 3 cm and x cm, find the value of x.
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Answer:
(4/3)π (4)^3 = (4/3)π {2^3 +3^3 + x^3}
4^3 = 2^3+3^3 +x^3
64 = 8 +27 + x^3
x^3 = 64 -8-27=29
x = cube root of 29 = 3(approximately)
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