a solid object in the shape of a double cone is traced by rotating a right angled triangle of smaller sides 12 cm and 5 cm about the hypotenuse of the triangle
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hypotenuse of the triangle=13
This will be the base of the cone of radius =13/2
We have to find the height of the cone
Height of the cone will be perpendicular distance from the 90 degree angle vertex to the hypotenuse = h
Area of the triangle=(1/2)×5×12=(1/2)×13×h
h=60/13
volume of the cone=(1/3)π(13/2)^2×60/13
=13×5=65 cm^3
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