Question

A solid object that weighs 300 N is placed on a wooden plank and a pressure of 60 N/m? is applied. What is the area of contact between the object and the wooden plank? (a) 2.5 m2 (b) 5.0 m2 (c) 10.0 m (d) 15.0 m2 ​

Answer 1

Explanation:

the answer is quite simple..

contact force=300N

pressure =60 N/M

as per formula p=f/a

300/60= 5m^2

I hope this helps..pls do mark my answer if you understand it

Answer 2

Given:

A solid object that weighs 300 N is placed on a wooden plank and a pressure of 60 N/m.

To find:

Area of contact?

Calculation:

• Pressure is defined as the magnitude of perpendicular force divided by the surface area on which the force acts.

$Pressure = \dfrac{Force}{area}$

$\implies 60 = \dfrac{300}{area}$

$\implies area= \dfrac{300}{60}$

$\implies area= 5.0 \: {m}^{2}$

So, area of contact between object and plank is 5.0 m².