Question

a solid object weighs 250 n. its base is rectangular in shape with a length of 50 cm and a breadth of 10cm. calculate the pressure exerted by the object on the floor where it is kept.​

Answer 1

Answer :-

Pressure exerted by the object on the floor where it is kept is 5000 Pascal .

Explanation :-

We have :-

→ Weight (Force) = 250 N

→ Length of the object = 50 cm

→ Breadth of the object = 10 cm

______________________________

Area of contact of the object :-

= Length × Breadth

= (50 × 10) cm²

= 500 cm²

Let's convert the unit of contact area from cm² to m² .

⇒ 1 cm² = 0.0001 m²

⇒ 500 cm² = 500(0.0001)

⇒ 0.05 m²

______________________________

Now, we know that :-

Pressure = Force/Contact area

⇒ Pressure = 250/0.05

⇒ Pressure = 250/(5/100)

⇒ Pressure = 25000/5

⇒ Pressure = 5000 Pa

Answer 2

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

★ Question :

• A solid object weighs 250 N. its base is rectangular in shape with a length of 50 cm and a breadth of 10cm. calculate the pressure exerted by the object on the floor where it is kept.

ㅤㅤㅤㅤㅤㅤ━━━━━━━━━━

★ Step by step explanation :

• Weight(force) of object = 250 N
• Length of the object = 50 cm
• Breadth of the object = 10 cm

★ Area of object in contact with floor :

➡ㅤㅤㅤArea = Length × Breadth

➡ㅤㅤㅤArea = 50 × 10

➡ㅤㅤㅤArea = 500 cm²

• Area in m² :

➡ㅤㅤㅤArea = 500/10000

➡ㅤㅤㅤArea = 0.05 m²

ㅤㅤㅤㅤㅤㅤ━━━━━━━━━━

★ Using formula :

$\qquad\red\bigstar\:{\underline{\boxed{\bf{Pressure = \dfrac{Force}{Area\:in\:contact}}}}}$

★ Putting all known values :

➥ㅤㅤㅤPressure = 250/0.05

➥ㅤㅤㅤPressure = 25000/5

➥ㅤㅤㅤPressure = 5000 pa

∴ Pressure exerted by the object when it ㅤis kept on floor = 5000 pa.

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬