Question

A solid of density 1800kg/m³ and volume 0.0015m³ is completely immersed in a liquid of density 800kg/m³ ,the apparent weight of solid in liquid is​

Answer 1

Answer:

A solid of density 2700 kgm' and of volume 0.0015 m3 ¡s completely immersed in alcohol of density 800 kgm'.Calculate : ... kg. Upthrust = Weight of liquid displaced by the glass cylinder

Explanation:

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Answer 2

Answer:

14.7 N

Explanation:

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Apparent weight is the weight of the body when it is freely suspended in a liquid

The reason for the apparent weight is because of buoyancy force acting on the body

Given,

Density of the solid (ρ) = 1800 kg/m³

Volume of the solid (V) = 0.0015 m³

We know that Density = Mass / Volume

Therefore,

Mass = Density x Volume

Applying the above formula,

Mass of the solid (m) = Density of the solid (ρ) x Volume of the solid (V)

m = 1800 x 0.0015

m = 2.7 kg

We know that the buoyancy force produced by the liquid on the body is equal to the

buoyancy force produced by the liquid on the body is equal to the Volume of the body immersed in the liquid x Density of the liquid x Acceleration due to gravity

Buoyancy force = V x ρ' x g , ρ' is the density of the liquid

Applying the above formula to find the buoyancy force applied by the liquid on the body,

Buoyancy force = 0.0015 x 800 x 9.8

Buoyancy force = 11.76 N

We know that Weight = Mass x Acceleration due to the gravity

W = mg

Applying the above formula,

Weight of the body = 2.7 x 9.8 = 26.46 N

To find the apparent weight of the body we have subtract the buoyancy force from weight of the body,

Apparent weight = Weight of the body - Buoyancy force

Applying the above formula,

Apparent weight = 26.46 - 11.76 = 14.7 N

Therefore,

The apparent weight of the body in the liquid = 14.7 N