Question

A solid of density 2500 kg/m³ and volume 0.002m³ is dipped completely in a liquid of density 700 kg/ m³.Find upthrust on the solid ​.Plz answer fast

Answer 1

Given

• Density = 2500 kg/m³
• Volume = 0.002 m³
• Density of liquid in which it is immersed = 700 kg/m³

To Find

• Upthrust force

Solution

☯ Mass = Density × Volume

• This can be used to find the mass of the solid. Then multiply it with 10 would give us the weight. 10 is the gravitational acceleration

☯ Mass (Liquid Displaced) = Volume × Density of liquid

━━━━━━━━━━━━━━━━━━━━━━━━━

✭ According to the Question :

→ Mass = Density × Volume

→ Mass = 2500 × 0.002

→ Mass = 5 kg

Weight of the solid would be,

→ Weight = mg

→ Weight = 5 × 10

→ Weight = 50 N

━━━━━━━━━━━━━━━━━━━━━━━━━

✭ Mass of liquid Displaced :

→ Mass (Liquid Displaced) = Volume × Density of liquid

→ Mass (Liquid Displaced) = 0.002 × 700

→ Mass (Liquid Displaced) = 1.4 kg

Therefore the upthrust would be,

• Upthrust = 1.4 × 10
• Upthrust = 14 N

∴ The buoyant force is 14 N

Answer 2

Answer:

Given :-

• Density of solid = 2500 kg/m³
• Volume = 0.002 m³
• Density of liquid = 700 kg/m³

To Find :-

Upthrust on solid

SoluTion :-

As we know that

$\frak \red{Mass = Density \times Volume}$

$\tt \implies \: Mass = 2500 \times 0.002$

$\frak \green{Mass = 5 \: kilogram}$

Now,

Finding weight of solid

$\frak \pink{W = mg}$

W is the weight

M is the mass

G is the Acceleration due to gravity

$\tt \implies \: W = 5 \times 10$

• Taking g as = 10 m/s

$\frak \green{W = 50 \:N }$

Now,

Finding mass of liquid Displaced

$\frak \red{Mass = Volume \times Density}$

$\tt \implies \: Mass = 0.002 \times700$

$\frak \pink{Mass = 1.4 \: kg}$

Hence

Upthrust would be

$\sf \: 1.4 \times 10 = 14 \: N$

Buayont force is 14 N.