Question

A solid of density 3000kg/m^3 weighs 0.3kgf in air.It is completely immersed in a liquid of density 1000 kg/m^3. The apparent weight of the solid is
i) 0.1kgf
ii) 0.2kgf
iii) 0.4kgf
iv) NONE OF THE ABOVE

Answer 1

Answer:

Density ρ  = 5000 kg/m  

3

 

Weight = 0.5 kg f in air

mass M = 0.5 kg  

Volume V = M / ρ  

          = 0.5 / 5000 = 10  

−4

m  

3

 

mass of water displaced = V  

∗

 density of water

 = 10  

−4

∗1000 = 0.1 kg  

Apparent weight = wt in air - wt of water displaced

                          = 0.5 kg f - 0.1 kg f  

                          = 0.4 kg f

Answer 2

Answer:

Density p = 5000kg/m

3

Weight = 0.5kg f in air

mass M =0.5 kg

volume V =M/p

= 0.5 /5000 = 10

-4

m

3

mass of water displaced = V

density of water

= 10

-4

* 1000 = 0.1 kg

Apparent weight = wt in air - wt of water displaced

0.5 kg f - 0.1 kg f

= 0.4 kg f

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