Question

A solid of density 4000 kg m^3 weighs 0.4 kgf in air. It is immersed completely in water of density 1000 kg m^3. Calculate the apparent welght of the solid in water.​

Answer 1

Answer:

0.3 kgf

Explanation:

Density ρ  = 4000 kg/m^3  

Weight = 0.4 kg f in air

mass M = 0.4 kg  

Volume V = M / ρ  

          = 0.4 / 4000 = 0.0001m^3

mass of water displaced = V*density of water    

0.0001 ∗1000 = 0.1 kg  

Apparent weight = wt in air - wt of water displaced

                          = 0.4 kgf - 0.1 kg f  

                          = 0.3 kgf