Question

A solid of density 5000 kg m to the power -3 weighs 0.5 kg f in air.it is completely immersed in water of density 1000 kg m to the power of -3.calculate the apparent weigh of the solid in water?

Answer 1

M=0.5 kg D=5000kg/m³ V=0.5/5000 =1/10⁴ Mass of water displaced =V×d =1/10⁴×10³=0.1kg W=0.1kgf Apparent wt= 0.5-0.1=0.4kgf