Question

a solid of density 5000 kg/m3 weighs 0.5 kgf in air. it is completely immersed in liquid of density 7800 kg/m3 calculate its apparent weight in SI units take g =10 m2​

Answer 1

Density ρ = 5000 kg/m

3

Weight = 0.5 kg f in air

mass M = 0.5 kg

Volume V = M / ρ

= 0.5 / 5000 = 10

−4

m

3

mass of water displaced = V

∗

density of water

= 10

−4

∗1000 = 0.1 kg

Apparent weight = wt in air - wt of water displaced

= 0.5 kg f - 0.1 kg f

= 0.4 kg f

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Answer 2

Answer:

1000 kg /m3

Explanation:

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