Question

A solid of density 5000 kg/m3 weighs 0.5 kgf in air. It is completely immersed in water of density 1000 kg/m3. Calculate the apparent weight of the solid in water.​

Answer 1

Answer:

0.4kg

Explanation:

Density ρ  = 5000 kg/m^3

Weight = 0.5 kg in air

mass M = 0.5 kg  

Volume V = M / ρ

          = 0.5 / 5000 = 10^-4 m^3  

mass of water displaced = V  ∗  density of water

= 10  ^−4 ∗1000 = 0.1 kg  

Apparent weight = wt in air - wt of water displaced

                          = 0.5 kg  - 0.1 kg  

                          = 0.4 kg