A solid of density 5000 kgm 3 weighs 0.5 kgf in air. It is completely immersed in a liquid of density 800 kgm ?. Calculate the apparent weight of the solid in liquid. [0.42 kgf]
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Answer:
Density ρ = 5000 kg/m³
Weight = 0.5 kg f in air
mass M = 0.5 kg
Volume V = M / ρ
= 0.5 / 5000 = 10-⁴m³
mass of water displaced = V * density of water = 10-⁴ ∗1000 = 0.1 kg
Apparent weight = wt in air - wt of water displaced
= 0.5 kg f - 0.1 kg f
= 0.4 kg f
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