Question

A solid of density 8000kgm^-3 , weight 0.8kgf in air. When it is completely submerged in a liquid of a density 5000kgm^-3,the weight appears to decrease. What is the apparent weight of the solid in the liquid?

Answer 1

Answer:

3000kgm^-3

Explanation:

Answer 2

Answer:

Explanation:

density ρ = 5000 kg/m³                 Weight = 0.5 kg f   in air

mass M = 0.5 kg

Volume V = M / ρ = 0.5 / 5000 = 10⁻⁴ m³

mass of water displaced = V * density of water 

     = 10⁻⁴ * 1000 = 0.1 kg

Apparent weight = wt in air - wt of water displaced

                          = 0.5 kg f - 0.1 kg f 

                           = 0.4 kg f