A solid of density p has weight W. Show that it's apparent weight will be [1-(pL/p)] when it is completely immersed in a liquid of density pL.
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→ Apparent weight of the solid = (Weight of solid in air) - (loss of weight of solid in liquid)
→ but, loss of weight of solid in liquid is equals to the weight of liquid displaced.
→ Thus, weight of liquid displaced is the product of Volume of solid and density of liquid.
∴ Volume of solid = W/D
where,
weight of solid = W
density = D
but, density of liquid = d.
→ Thus, weight of liquid displaced = w.d / D = Loss of weight of solid into liquid.
∴ Apparent weight = W - W.d / D
= W (1 - d/D)
→ Hence, apparent weight of the solid is W (1 - d/D).
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Answer:
answer. the proof has been given above.
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