Question

a solid of mass 0.15 kg is heated from 10 degree to 90 degree if the specific heat capacity of a solid is 390 joules kg cell degree Celsius then the heat absorbed by solid​

Answer 1

Answer:

Explanation:

m= 0.15 kg = 15/100 kg

C= 390 Jkg -10C-1

rise in temp. =  90-10 = 80

∴ Heat absorbed by solid = mcΔt = 15/100 x 390 x 80 = 4680J

Answer 2

answer:

m= 0.15,

t=90-10=80,

s=390,

q=?

s=q/mt

390=q×0.15×80

390=q×12

q=390×12

q=4680