A solid of mass 100 g at 150oC is placed in 100 g of water at 11oC, when the final temperature recorded is 20oC. Find the specific heat capacity of the solid.
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Answer:
Mass of solid m
s
=50 g
Temperature of solid T
s
=150
o
C
Let the Specific heat capacity of solid be S
s
.
Mass of water m
w
=100 g
Temperature of water T
w
=11
o
C
Specific heat capacity of water S
w
=4.2 J/g
o
C
Final temperature T
f
=20
o
C.
Heat released by the solid is equal to the heat absorbed by water in order to achieve equilibrium.
∴ m
s
S
s
(T
s
−T
f
)=m
w
S
w
(T
f
−T
w
)
Or 50×S
s
(150−20)=150×4.2×(20−11)
⟹ S
s
=0.87 J/g
o
C
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