Question

A solid of mass 50g at 150° C is placed in 100 g of water at 11° C, when the final
pan general
2,
122
temperature recorded is 20°С. Find the specific heat capacity of the solid.
Specific heat capacity of water = 4.2 j/g° C)
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Answer 1

Answer:

Mass of solid ms=50g

Temperature of solid ts=150°C

Let the specific heat capacity of solid be Ss

Mass of water mw= 100g

Temperature of water tw=11°C

Specific heat capacity of water Sw=4.2J/g°C

final temperature Tf =20°C

Hence release by the solid is equal to the heat absorbed by water in order to achieve equilibrium.

: MsSs(Ts-Tf)=Mwsw(Tf-Tw)

50xSs(150-20)=150x4.2x(20-11)

=Ss=0.87J/g°C