Question

A solid of R.D. 2.5 is found to weigh 0.120 kgf in water. Find the wt. of solid in air.​

Answer 1

Step-by-step explanation:

Weight of the solid in air, W

1

=32 gf

weight of the solid immersed completely in water, W

2

=28.8 gf

density of the liquid =0.9 gcm

−3

To find the R.D. of the solid

Relative density of the solid =

W

3

−W

2

W

1

× relative density of water

=

32−28.8

32

×1=10

Answer 2

Answer:

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