Question

A solid of R.D. 4.2 is found to weigh 0.200 kgf in air. Find its apparent weight in water

Answer 1

$\huge\underline\orange{\mathcal Answer}$

$\large\blue{\boxed{\mathcal Apparent\:Weight\:Of\:Water(x) = 0.153}}$

$\huge\underline\orange{\mathcal Solution :-}$

Given :-

Relative density (RD) = 4.2

Weight in air = 0.200kgf

Weight in water = x

$\large{\boxed{\mathcal RD={\frac{Weight\:In\:Air}{Weight\:In\:Air-Weight\:In\:Water}}}}$

$\large{\mathcal 4.2={\frac{0.200}{0.200-x}}}$

$\large{\mathcal 0.84-4.2x=0.200}$

$\large{\mathcal 0.84-0.200=4.2x}$

$\large{\mathcal 0.640=4.2x}$

$\large{\mathcal x={\frac{0.640}{4.2}}}$

$\huge{\boxed{\mathcal x = 0.153kgf}}$

Hence, Apparent weight in water is 0.153 kgf

$\huge\orange{\mathcal Hope\:It\:Helps!!!}$