Question

A solid of weight 200 gf when half immersed in a liquid of R.D = 2 weighs 160 gf. Determine the
volume of solid.
Hence calculate its weight when completely immersed in water.
Pls Answer this question fast​

Answer 1

Answer:

Using Montesquieu's formula,

v = wr

Hence v = 200 gf × 160 gf : 2 = 32000:2 gf = 16000 gf....

hope this helps