Math, asked by Kannan0017, 8 months ago

A solid piece of iron in the form of a cuboid of dimensions 49cm × 33cm × 24cm, is moulded to form a solid sphere. The radius of the sphere is

Answers

Answered by Anonymous
45

\large{\underline{\rm{\purple{\bf{Given:-}}}}}

Length of the cuboid = 49 cm

Breadth of the cuboid = 33 cm

Height of the cuboid = 24 cm

\large{\underline{\rm{\purple{\bf{To \: Find:-}}}}}

The radius of the sphere.

\large{\underline{\rm{\purple{\bf{Solution:-}}}}}

Given that,

Length (l) = 49 cm

Breadth (b) = 33 cm

Height (h) = 24 cm

We know that,

\boxed{\sf Volume \: of \: cuboid = lbh}

Substituting their values,

Volume of the cuboid = \sf 49 \times 33 \times 24 \: cm^{3}

Now,  let us consider the radius of cube to be 'r'

As volume of sphere = \sf \dfrac{4}{3} \pi r^{3}

Where, r = radius of sphere

Volume of cuboid = volume of sphere molded

Therefore, according to the question

\implies \sf 43(33)(24)=\dfrac{4}{3} \pi r^{3}

\implies \sf \pi r^{3} = 29106

\implies \sf r^{3} = 29106 \times \dfrac{22}{7}

\implies \sf r^{3} = 9261

\implies \sf r=\sqrt[3]{9261} =21

Therefore, the radius is 21 cm

Answered by cyril10n07
12

Answer:

as per the question volume of cuboid=volume of sphere

volume of cuboid=lbh cubic cm

                          =38808cm3

volume of sphere =4/3pi r cube

4/3 pi r cube=38808cubic cm

            r cube =38808x21/4x22

                  r=21 cm

Step-by-step explanation:

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