Math, asked by tvnvs380, 5 months ago

.A solid piece of iron in the form of a cuboid of dimensions 49cm × 33cm × 24cm, is moulded to form a solid sphere. The radius of the sphere is *
1 point
(a) 21cm
(b) 23cm
(c) 25cm
(d) 19cm​

Answers

Answered by IIMidnightHunterII
4

\LARGE\textbf{\underline{\underline{Answer :- }}}

\boxed{\large\textbf{( a ) 21 cm}}

\LARGE\textbf{\underline{Given :- }}

  • Dimensions of the cuboid are = 49cm , 33cm , 24cm.

\LARGE\textbf{\underline{To find :- }}

  • If the cuboid is moulded in Sphere then what would be the radius of the sphere.

\LARGE\textbf{\underline{Formulas :- }}

  • \boxed{\large\textbf{Volume of the cuboid = L × B × H}}

  • \boxed{\large\textbf{Volume of a Sphere = $\cfrac{4}{3} × \pi × r ^{3}$}}

\LARGE\textbf{\underline{Here :- }}

  • L = LENGTH
  • B = BREADTH
  • H = HEIGHT
  • R = RADIUS
  • π = 22/7

\LARGE\textbf{\underline{Solution :- }}

⟾ As the cuboid is moulded into the sphere so first we have to find the volume of the cuboid.

  • \large\textbf{Volume of the cuboid = 49 × 33 × 24}

  • \boxed{\large\textbf{Volume of the cuboid = 38808 cu.cm}}

⟾ As this volume of the cuboid we have to mould in to the sphere so this volume would also be the volume of the sphere which we have to make.

\boxed{\therefore\large\textbf{Volume of Sphere = $\cfrac{4}{3} × \cfrac{22}{7} × r^{3}$}}

\therefore\large\textbf{38808 =  $\cfrac{4}{3} × \cfrac{22}{7} × r^{3}$}

\therefore\large\textbf{$\cfrac{38808 × 3 × 7}{4 × 22} = r^{3} $}

\therefore\large\textbf{ $9361 = r^{3}$}

\therefore\large\textbf{ $\sqrt[3]{9361} = r$}

\boxed{\therefore\large\textbf{21 = r}}

⟾So the radius of the sphere moulded from the cuboid is 21 cm.

\LARGE\textbf{\underline{\underline{More Formal:- }}}

OF CUBOID :-

  • \large\textbf{Lateral surface area = 2H ( L + B)}

  • \large\textbf{Total surface area = 2 ( LB + BH + HL )}

  • \large\textbf{ Volume = L × B × H}

  • H = HEIGHT
  • B = BREADTH
  • L = LENGTH

OF SPHERE :-

  • \large\textbf{Surface area =$ = 4 × \pi × r^{3}$}

  • \large\textbf{Volume =$ \cfrac{4}{3} × \pi × r^{3} $}

  • r = Radius
  • π = 22/7 or 3.14

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