Question

A solid piece of iron is in the form of a cuboid of dimension 10 into 5 into 2 find its total surface area

Answer 1

Answer:

Surface area of a cuboid =2(lb+bh+hl)

l=10,b=5and h =2

=2(10. 5+5.2+2.10)

=2(50+10+20)

=2(80)

=160

Answer 2

Given :

The dimensions of a solid piece of iron cuboid is 10 × 5 × 2.

To Find :

Total surface area of the cuboid.

Solution :

Length of the cuboid = 10

Width of the cuboid = 5

Height of the cuboid = 2

Formula of surface area for cuboid = 2(lw) + 2(hl) + 2(hw)

= 2(10×5) + 2(2×10) + 2(2×5)

= 2(50) + 2(20) + 2(10)

= 100 + 40 + 20

= 160 unit²

Total surface area of the cuboid 160 unit².