Question

A solid piece of iron is in the form of a cuboid of
dimensions (49cm × 33cm × 24cm) is melted and
moulded to form a solid sphere. The radius of the
sphere is:

Answer 1

as per the question volume of cuboid=volume of sphere
volume of cuboid=lbh cubic cm
                           =38808cm3
volume of sphere =4/3pi r cube
4/3 pi r cube=38808cubic cm
             r cube =38808x21/4x22
                   r=21 cm

Answer 2

Answer:

21 cm

Step-by-step explanation:

Length of cuboid = 49 cm

Breadth of cuboid = 33 cm

Height of cuboid = 24 cm

Volume of cuboid = $Length \times Breadth \times Height$

                              = $49 \times 33 \times 24$

                              = $38808 cm^3$

Volume of sphere = $\frac{4}{3} \pi r^3$

Since The cuboid is melted and  moulded to form a solid sphere.

So, volume will remain same

So, $38808=\frac{4}{3} \pi r^3$

$38808=\frac{4}{3} \times \frac{22}{7}\times r^3$

$38808 \times \frac{3}{4} \times \frac{7}{22} = r^3$

$9261= r^3$

$\sqrt[3]{9261}= r$

$21= r$

Hence The radius of the  sphere is 21 cm.