Question

A solid piece of iron of dimensions 49×33×24 cm is moulded into a sphere.The radius of the sphere is

Answer 1

dimensions of cuboidal iron = 49×33×24
Volume of cuboid = lbh=49×33×24=38808 cm sq.
volume of sphere =
$4 \div 3\pi {r}^{2}$
volume of cuboid = volume of sphere
$38808 = 4 \div 3\pi {r}^{2}$
$38808 \times 3 \div 4 \div \pi = {r}^{2}$
$9264 = { r }^{2} \\ \sqrt{9264 } = r \\ r = 96$