Chemistry, asked by jazmin80glz1, 1 year ago

A solid reactant is placed into a beaker of a warm water. The liquid vigorously bubbles as the solid dissolves into the solution. What will most likely happen if the temperature of the liquid is slightly reduced?
More bubbles will be produced because the solution is becoming more concentrated.
Fewer bubbles will be produced because of fewer collisions of reactant molecules.
The solid will get smaller at a faster rate because of more collisions of reactant molecules.
The solid will get larger at a slower rate because precipitate is coming out of the solution.

Answers

Answered by eudora
24

Answer : Fewer bubbles will be produced because of fewer collisions of reactant molecules.

The rate of the reaction depends on the number of successful collisions between the reacting molecules.

As the temperature increases, the speed with which the molecules move increases. This in turn increases the number  of collisions. As a result rate of the reaction also increases with an increase in temperature.

For the given reaction, when the temperature of the liquid is reduced, it reduces the number of successful collisions and therefore the rate of the reaction also decreases.

This decrease in rate is indicated by fewer bubbles coming out of the solution.

Therefore the correct option is "Fewer bubbles will be produced because of fewer collisions of reactant molecules."

Answered by bh23055
10

Answer:

B. Fewer bubbles will be produced because of fewer collisions of reactant molecules.

Explanation:

EDG21 I took the quiz

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