Question

A solid receives heat by radiation over its surface at the rate of 4 kW. The heat convection rate from the surface of solid to the surrounding is 5.2 kW. and heat is gencrated at a rate of 1.7 kW over the volume of the solid. The rate of change of the average temperature of the solid is 0.5 Cs.Find the heat capacity of the solid.

Answer 1

Dear Student,

◆ Answer -

c = 1000 J/℃

● Explanation -

Total rate of change of heat for the solid is calculated by -

Rate of heat change = rate of heat received + rate of heat generation - rate of heat convection

Substituting values -

dQ/dt = 4 + 1.7 - 5.2

dQ/dt = 0.5 kW

Heat capacity of the solid is calculated by -

c = (dQ/dt) / (dT/dt)

c = 0.5 / 0.5

c = 1 kJ/℃

c = 1000 J/℃

Therefore, heat capacity of the solid is 1000 J/℃.