Question

A solid rectangular piece of Iron measure
6m by 6m by 2m an find the weight
of this piece if 1cm3 of Iron
weighs 8gm​

Answer 1

★ Given:

Length of cuboidal iron piece = 6 m

Breadth of the iron piece = 6 m

Height of the iron piece = 2 m

Weight of 1 cm³ iron = 8 g

★ To Find:

The total weight of this iron piece.

★ Analysis

In this question, we first have to find the volume of the cuboid and them multiply the volume with the weight of 1 cm³ of the cuboid.

★ Formulae to be used:

→ $\sf{Volume\:of\:cuboid=lbh}$

→ $\sf{1\:m^3=1000000\:cm^3}$

★ Solution:

Length = 6 m

Breadth = 6 m

Height = 2 m

Volume of any cuboid = lbh

Volume of given cuboid = 6 x 6 x 2

= 6 x 12

= 54 m³

1 m³ = 1000000 cm³

So,

54 m³ = 54 x 1000000 cm³

= 54000000 cm³

Weight of 1 cm³ iron = 8 g

So, weight of 54000000 cm³ iron

= 54000000 x 8

= 432000000 g

= 432000 kg

Hence the required answer is 432000 kg [432000000 g].

Answer 2

Answer:

Given:-

$\begin{gathered} \sf \: Length \: of \: cuboidal \: iron \: piece = 6 m \end{gathered}$

$\begin{gathered} \sf \: Breadth \: of \: the \: iron \: piece = 6 m \end{gathered}$

$\begin{gathered} \sf \: Height \: of \: the \: iron \: piece = 2 m \end{gathered}$

$\begin{gathered} \sf \: Weight \: of \: 1 cm {}^{3} \: iron = 8 g \end{gathered}$

★ To Find:

The total weight of this iron piece.

★ Analysis

In this question, we first have to find the volume of the cuboid and them multiply the volume with the weight of 1 cm³ of the cuboid.

★ Formulae to be used:

$→ \sf{Volume\:of\:cuboid=lbh}Volumeofcuboid=lbh$

$→ \sf{1\:m^3=1000000\:cm^3}1m$

★ Solution:

Length = 6 m

Breadth = 6 m

Height = 2 m

Volume of any cuboid = lbh

Volume of given cuboid = 6 x 6 x 2

= 6 x 12

= 54 m³

1 m³ = 1000000 cm³

So,

54 m³ = 54 x 1000000 cm³

= 54000000 cm³

Weight of 1 cm³ iron = 8 g

So, weight of 54000000 cm³ iron

= 54000000 x 8

= 432000000 g

= 432000 kg

Hence the required answer is 432000 kg [432000000 g].