A solid right circular cone of diameter 14 cm and height 8 cm is melted to form a hollow sphere. If the external diameter of the sphere is 10 cm, find the internal diameter of the sphere .
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we have ,
in a right circular cone
d = 14 cm , r = 14/2 =7 cm
h = 8 cm
& in hollow sphere
external diameter (d1)= 10 cm , r1 = 10/2 =5 & internal diameter(d2) = ?
then ,
v. of cone = v . of hollow sphere
1/3πr2h = 4/3π(r31-r32)
1/3 * 7*7*8 = 4/3 (53- r32)
1*7*7*8 = 4 (125 - r32)
49*8 =4 (125- r32)
392/4= (125-r32)
98 -125 = - r32
- 27 = - r32
3 = r 2
so, internal radius ( r 2 ) = 3 cm
internal diameter ( d2) = 2*3 = 6cm
hence , d2 = 6cm
in a right circular cone
d = 14 cm , r = 14/2 =7 cm
h = 8 cm
& in hollow sphere
external diameter (d1)= 10 cm , r1 = 10/2 =5 & internal diameter(d2) = ?
then ,
v. of cone = v . of hollow sphere
1/3πr2h = 4/3π(r31-r32)
1/3 * 7*7*8 = 4/3 (53- r32)
1*7*7*8 = 4 (125 - r32)
49*8 =4 (125- r32)
392/4= (125-r32)
98 -125 = - r32
- 27 = - r32
3 = r 2
so, internal radius ( r 2 ) = 3 cm
internal diameter ( d2) = 2*3 = 6cm
hence , d2 = 6cm
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