A solid right circular cone of height 120 cm and radius 60 centimetres is placed on a right circular cylinder full of water of height 180 centimetre such that it touches the bottom. Find the volume of water left in the cylinder is the radius of the cylinder is equal to that of the radius of the cone
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height of cone=h=120cm
height of cylinder=H=180cm
radius of cone=radius of cylinder=60cm
volume of water left in the cylinder=volume of
cylinder-volume of cone
=πr^2H-1/3πr^2h
=πr^2(H-1/3h)
=22/7×60×60(180-1/3×120)
=22/7×3600(180-40)
=22/7×3600×140
=22×3600×20
=1,584,000cm^3
1 litre=1000cm^3
1 cm^3=1/1000litre
1,584,000cm^3=1,584,000/1000
=1584litre.
height of cylinder=H=180cm
radius of cone=radius of cylinder=60cm
volume of water left in the cylinder=volume of
cylinder-volume of cone
=πr^2H-1/3πr^2h
=πr^2(H-1/3h)
=22/7×60×60(180-1/3×120)
=22/7×3600(180-40)
=22/7×3600×140
=22×3600×20
=1,584,000cm^3
1 litre=1000cm^3
1 cm^3=1/1000litre
1,584,000cm^3=1,584,000/1000
=1584litre.
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