a solid right circular cone of radius 4cm an height 7cm is melted to form a shere find the radius of sphere
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3
according to the question,
volume of cone = volume of sphere.
1/3 * pi * r^2 * h = 4/3 * pi * r^3
pi and pi are cancelled.
1/3 * 4^2 * 7 = 4/3 * r^3
1/3 * 112 = 4/3 * r^3
r^3 = 112/3 * 3/4
r^3 = 28
therefore radius of sphere = 3 root 28
volume of cone = volume of sphere.
1/3 * pi * r^2 * h = 4/3 * pi * r^3
pi and pi are cancelled.
1/3 * 4^2 * 7 = 4/3 * r^3
1/3 * 112 = 4/3 * r^3
r^3 = 112/3 * 3/4
r^3 = 28
therefore radius of sphere = 3 root 28
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Answered by
2
Volume of cone=⅓πr²h
=⅓×22/7×4×4×7 cm³
=⅓×22×4×4 cm³
=352/3 cm³
Volume of sphere=Volume of cone
4/3πr³=352/3 cm³
4×22/7×r³=352/3×3 cm³
r³=352×7/4×22
r³=16×7/4
r³=4×7
r=³√28
=⅓×22/7×4×4×7 cm³
=⅓×22×4×4 cm³
=352/3 cm³
Volume of sphere=Volume of cone
4/3πr³=352/3 cm³
4×22/7×r³=352/3×3 cm³
r³=352×7/4×22
r³=16×7/4
r³=4×7
r=³√28
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