A solid right circular cylinder of radius 8 cm qnd height 3times that of cylinder find the curved surface area of cone
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height of the cylinder = 3cm
radius of the cylinder = 8cm
volume of a cylinder = πr^2h
= 22 * 64 * 3 / 7
= 66*64/7cm3
height of the cone = 3 times that of cylinder
= 3 x 3 = 9cm
volume of the cylinder = volume of the cone ( since it is melted out of the cylinder)
volume of the cone = 66*64/7 cm3
volume of the cone = 2/3 πr^2l
= 1*22*r2*9 / 3*7
= 66/7 r2cm3
==> 66/7r2 = 66*64/7
==> r2 = 64
then r =8cm
thus the radius of the cone is 8cm
slant height of a cone = sqrt. (h2+r2)
= sqrt. (81+6 = sqrt. (145)
csa of a cone = πrl
= 22*8*sqrt.145 / 7 = cm2 (approx)
radius of the cylinder = 8cm
volume of a cylinder = πr^2h
= 22 * 64 * 3 / 7
= 66*64/7cm3
height of the cone = 3 times that of cylinder
= 3 x 3 = 9cm
volume of the cylinder = volume of the cone ( since it is melted out of the cylinder)
volume of the cone = 66*64/7 cm3
volume of the cone = 2/3 πr^2l
= 1*22*r2*9 / 3*7
= 66/7 r2cm3
==> 66/7r2 = 66*64/7
==> r2 = 64
then r =8cm
thus the radius of the cone is 8cm
slant height of a cone = sqrt. (h2+r2)
= sqrt. (81+6 = sqrt. (145)
csa of a cone = πrl
= 22*8*sqrt.145 / 7 = cm2 (approx)
Answered by
3
therefore the answer is 302.72cm^.
I hope this helps you
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